Question

In throwing a die one time, what is the probability of not appearing 2?

• A. \(0\)
• B. \(16\)
• C. \(\tfrac{5}{6}\)
• D. \(\tfrac{1}{2}\)

Hint:

Probability = \(\frac{\text{Favorable}}{\text{Total}}\). Exclude unwanted outcome(s).

Answer 1

The Correct Option is C

Step 1: Total outcomes of a die.
There are 6 equally likely outcomes.
Step 2: Favorable for not getting 2.
5 outcomes: {1,3,4,5,6}.
Step 3: Probability.
\[ P(\text{not 2})=\frac{5}{6} \]