Step 1: Name the four unknown groups.
Since every student picks exactly one of Systems, Operations or HR, split Systems and Operations by gender. Let p = girls in Systems, q = girls in Operations, r = boys in Systems, s = boys in Operations.
Step 2: Turn each sentence into an equation.
"Girls in Operations plus boys in Systems is 37" gives \(q + r = 37\). "Twenty-two students opted for Operations" gives \(q + s = 22\). "Twenty girls opted for Systems and Operations put together" gives \(p + q = 20\). "Students in Systems plus boys in Operations is 37" gives \((p + r) + s = 37\).
Step 3: Reduce to one unknown.
From the third equation, \(p = 20 - q\). From the second equation, \(s = 22 - q\). Substitute both into the fourth equation:
\[ (20 - q + r) + (22 - q) = 37 \] \[ 42 - 2q + r = 37 \] \[ r = 2q - 5 \]
Step 4: Solve for q, then the rest.
Put \(r = 2q - 5\) into the first equation, \(q + r = 37\):
\[ q + (2q - 5) = 37 \implies 3q = 42 \implies q = 14 \]
So \(r = 2(14) - 5 = 23\), \(p = 20 - 14 = 6\), and \(s = 22 - 14 = 8\).
Step 5: Add up the second year.
Systems total \(= p + r = 6 + 23 = 29\). Operations total is already given as 22, and HR total is given as 25. So the second year has:
\[ 29 + 22 + 25 = 76 \]
The nearby wrong options (73, 74, 75, 77) all come from a slip somewhere in this chain, such as mixing up which sum is 20 and which is 37, or forgetting that the Systems total is \(p + r\) and not just one of the two parts. Working through the four equations in the order above avoids that.
Final Answer:
The number of students in the second year is 76.\[ \boxed{76} \]