Question:

In the removal of permanent hardness of water by permutit process, \(Na^+\) ions of permutit are exchanged with which ions of water?

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Permanent hardness is mainly due to \(Ca^{2+}\) and \(Mg^{2+}\). Permutit removes these ions by ion exchange with \(Na^+\).
  • \(K^+,\ Ba^{2+}\)
  • \(Fe^{2+},\ K^+\)
  • \(Ca^{2+},\ Mg^{2+}\)
  • \(Zn^{2+},\ Cu^{2+}\)
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The Correct Option is C

Solution and Explanation

Permanent hardness of water is mainly due to dissolved salts of calcium and magnesium. The responsible ions are: \[ Ca^{2+} \] and \[ Mg^{2+}. \] In the permutit process, sodium zeolite or permutit is used. It contains exchangeable sodium ions: \[ Na^+. \] When hard water is passed through permutit, calcium and magnesium ions are exchanged with sodium ions. For example: \[ Ca^{2+}+Na_2Z\rightarrow CaZ+2Na^+. \] Similarly: \[ Mg^{2+}+Na_2Z\rightarrow MgZ+2Na^+. \] Thus, \(Na^+\) ions of permutit are exchanged with: \[ Ca^{2+},\ Mg^{2+}. \]
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