In the reaction sequence
\(2\,\mathrm{CH_3CHO}\xrightarrow{\mathrm{OH^-}}\mathrm{A}\xrightarrow{\Delta}\mathrm{B}\) ; the product B is :
\(2\,\mathrm{CH_3CHO}\xrightarrow{\mathrm{OH^-}}\mathrm{A}\xrightarrow{\Delta}\mathrm{B}\) ; the product B is :
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- \(\mathrm{CH_3-CH_2-CH_2-CH_2-OH}\)
- \(\mathrm{CH_3-CH=CH-CHO}\)
- \(\mathrm{CH_3-CO-CH_3}\)
- \(\mathrm{CH_3-CH_2-CH_2-CH_3}\)
The Correct Option is B
Solution and Explanation
Step 2 (heat): the beta-hydroxy aldehyde loses H2O (the alpha hydrogen and the beta OH) to give the conjugated aldehyde B = CH3CH=CHCHO (but-2-enal, crotonaldehyde).
Answer: (2) CH3-CH=CH-CHO
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