To solve this problem, we need to examine the organic compound \(CH_2 = CH-CH_2-CH_2-C≡CH\) and determine the types of hybridized orbitals involved in the \(C_2 – C_3\) bond.
Firstly, identify the structure of the compound and the types of bonds:
\(CH_2 = CH-CH_2-CH_2-C≡CH\) is composed of a chain where:
\(C_1\) is attached to \(CH_2\) (double bond),
\(C_2\) is part of a double bond \((CH_2 = CH-)\),
\(C_3\) is part of single bonds on either side \((-CH_2-CH_2-)\),
\(C_4\) is bonded again to single-bonded carbon,
\(C_5\) is part of the triple bond \((-C≡CH)\).
Identify the hybridization of the involved carbons:
Carbon \(C_2\) is part of a double bond \(CH_2 = CH-\), which is typically \(sp^2\) hybridized.
Carbon \(C_3\) is part of single bonds to form \(CH_2\), which is typically \(sp^3\) hybridized.
For the bond \(C_2 – C_3\), the pair of hybridized orbitals involved are those from these two carbon atoms:
The \(C_2\) (double bond portion) is \(sp^2\) hybridized.
The \(C_3\) (adjacent single bond portion) is \(sp^3\) hybridized.
Thus, the pair of hybridized orbitals involved in the formation of the \(C_2 – C_3\) bond is \(sp^2-sp^3\).
In conclusion, the correct answer is actually \(sp^2-sp^3\), not the provided correct answer, as there seems to be an error in the key solution.
Organic Chemistry – Some Basic Principles and Techniques - Reaction Mechanism
SN1 Reaction Mechanism:
SN1 reaction mechanism takes place by following three steps –
Formation of carbocation
Attack of nucleophile
Deprotonation
SN2 Reaction Mechanism:
The SN2 reaction mechanism involves the nucleophilic substitution reaction of the leaving group (which generally consists of halide groups or other electron-withdrawing groups) with a nucleophile in a given organic compound.
