Question

In the neighborhood of z = 1, the function f(z) has a power series expansion of the form f(z) = 1+(1-z)+(1-z)² + .... then f(z) is

• A. \(\frac{1}{z}\)
• B. \(\frac{-1}{z-2}\)
• C. \(\frac{1}{2z-1}\)
• D. \(\frac{z-1}{z+1}\)

Answer 1

The Correct Option is A

The correct answer is(A): \(\frac{1}{z}\)