Question:

In the given reaction sequence, the major product 'C' is :

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\(\mathrm{C_8H_{10}}\) is ethylbenzene: nitration goes mainly para, bromination with heat occurs at the benzylic position, and alcoholic KOH gives elimination to the alkene.
Updated On: Nov 4, 2026
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The Correct Option is B

Solution and Explanation

\(\mathrm{C_8H_{10}}\) (ethylbenzene) with \(\mathrm{HNO_3/H_2SO_4}\): the ethyl group is an ortho/para director and the para product is major, so A is 4-nitroethylbenzene.
A with \(\mathrm{Br_2}\) and heat: free-radical bromination at the benzylic carbon, so B is 1-(1-bromoethyl)-4-nitrobenzene.
B with alcoholic KOH: E2 dehydrohalogenation, so C is 4-nitrostyrene, \(\mathrm{O_2N{-}C_6H_4{-}CH{=}CH_2}\).
This is the structure in option (2).
Answer: (2) 4-nitrostyrene
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