
To determine the number of secondary (2°) carbon atoms in the given compound, we need to understand the definition of a 2° carbon atom. A secondary carbon atom is a carbon atom bonded to two other carbon atoms.
Analyzing the structure, we identify the types of carbon atoms:
Therefore, the number of secondary (2°) carbon atoms in the compound is one.
Thus, the correct answer is: One.
To determine the number of secondary (2°) carbon atoms in the given compound, we need to understand the definition of a secondary carbon atom. A secondary carbon atom is bonded to two other carbon atoms.
Let's analyze the given compound structure:
After examining the structure, we can confirm that there is only one secondary carbon atom present in the compound.
Therefore, the correct answer is: One
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)