Question:

In the following brown complex, the oxidation state of iron is +_____________.

\( {[Fe{({H_2}O)_6}]^{2 + }} + NO \to \mathop {{{[Fe{{({H_2}O)}_5}(NO)]}^{2 + }}}\limits_{\text{Brown complex}} + {H_2}O \)

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In the brown-ring complex the nitrosyl ligand is NO+; use the overall charge of the complex ion to find the oxidation state of Fe.
Updated On: Oct 31, 2026
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Correct Answer: 1

Solution and Explanation

Step 1: The complex ion is \([Fe(H_2O)_5(NO)]^{2+}\). H2O is neutral. In the brown-ring complex, NO is present as the nitrosonium ligand NO+ (Fe2+ transfers one electron to NO).
Step 2: Let the oxidation state of Fe be x. Then \(x + 5(0) + (+1) = +2\).
Step 3: \(x = +1\).
Answer: 1
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