Question:
In the expansion of $\frac{C_1}{C_0} + 2\frac{C_2}{C_1} +3\frac{C_3}{C_2}+…………… n \frac{C_{n}}{C_{n-1}}$ is equal to
In the expansion of $\frac{C_1}{C_0} + 2\frac{C_2}{C_1} +3\frac{C_3}{C_2}+…………… n \frac{C_{n}}{C_{n-1}}$ is equal to
Updated On: Nov 10, 2025
- $ \frac {n(n+1)}2$
- $\frac {n}2 $
- $\frac {n+1}2 $
- $ 3n(n+1)$
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The Correct Option is A
Solution and Explanation
The correct answer is Option (A) : $ \frac {n(n+1)}2$
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