In electrolysis of molten NaCl:
- Only Na⺠and Cl⻠ions are present.
- At cathode (reduction):
\[
\text{Na}^+ + e^- \rightarrow \text{Na} \quad \text{(sodium metal)}
\]
- At anode (oxidation):
\[
2\text{Cl}^- \rightarrow \text{Cl}_2 + 2e^-
\]
So, Na metal is deposited at the cathode.
Answer: \( \boxed{\text{Na metal}} \)