Question:
In the circuit with ideal devices, the power MOSFET is operated with a duty cycle of 0.4 in a switching cycle with \( I = 10 \, {A} \) and \( V = 15 \, {V} \). The power delivered by the current source, in W, is: \[ {(round off to the nearest integer).} \]
In the circuit with ideal devices, the power MOSFET is operated with a duty cycle of 0.4 in a switching cycle with \( I = 10 \, {A} \) and \( V = 15 \, {V} \). The power delivered by the current source, in W, is: \[ {(round off to the nearest integer).} \]
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For switching circuits with ideal devices, the average power delivered by a current source is given by:
\[
P = I \cdot V_{{across source}} \cdot (1 - D)
\]
where \( D \) is the duty cycle and the source voltage appears during the OFF time.
Updated On: Feb 3, 2026
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Correct Answer: 90
Solution and Explanation
This is a typical buck-boost or switched-mode circuit. The power source delivers current \( I = 10 \, {A} \) continuously, but voltage is only applied across the load during the **off** time of the MOSFET.
Given:
- Duty cycle \( D = 0.4 \)
- So switch is OFF for \( 1 - D = 0.6 \) fraction of time
- During OFF time, the diode conducts and the voltage across the current source is \( V = 15 \, {V} \)
Average power delivered by the source:
\[
P = I \cdot V \cdot (1 - D) = 10 \cdot 15 \cdot 0.6 = 90 \, {W}
\]
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