




The given chemical reaction involves the conversion of benzyl alcohol to benzyl iodide. Here is the step-by-step explanation:
1. **Reaction with HCl:**
The primary alcohol group (CH2OH) in benzyl alcohol reacts with hydrochloric acid (HCl) to form benzyl chloride (compound A) through a nucleophilic substitution reaction.
2. **Mechanism:**
3. **Reaction with NaI:**
Next, benzyl chloride reacts with sodium iodide (NaI) in an SN2 reaction mechanism to form benzyl iodide (compound B).
4. **Final Product (B):**
The final product, compound B, is benzyl iodide (C6H5-CH2I), represented by the option CH2I-OH.
This is consistent with the mechanism for the formation of iodoalkanes from chloroalkanes using sodium iodide (Finkelstein reaction), where iodide ions, being strong nucleophiles, displace the chlorine atom.

Product B is \(4-iodomethylphenol.\)
The correct answer is (A): 






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