




The given chemical reaction involves the conversion of benzyl alcohol to benzyl iodide. Here is the step-by-step explanation:
1. **Reaction with HCl:**
The primary alcohol group (CH2OH) in benzyl alcohol reacts with hydrochloric acid (HCl) to form benzyl chloride (compound A) through a nucleophilic substitution reaction.
2. **Mechanism:**
3. **Reaction with NaI:**
Next, benzyl chloride reacts with sodium iodide (NaI) in an SN2 reaction mechanism to form benzyl iodide (compound B).
4. **Final Product (B):**
The final product, compound B, is benzyl iodide (C6H5-CH2I), represented by the option CH2I-OH.
This is consistent with the mechanism for the formation of iodoalkanes from chloroalkanes using sodium iodide (Finkelstein reaction), where iodide ions, being strong nucleophiles, displace the chlorine atom.

Product B is \(4-iodomethylphenol.\)
The correct answer is (A): 
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are

Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R.
Assertion A: H2Te is more acidic than H2S.
Reason R: Bond dissociation enthalpy of H2Te is lower than H2S.
In light of the above statements, choose the most appropriate from the options given below:


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)






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