In the \( ^1H \) NMR spectrum, which one of the following compounds will show a triplet?
In the \( ^1H \) NMR spectrum, which one of the following compounds will show a triplet?
Show Hint
- (A)
- (B)
- (C)
- (D)
The Correct Option is A
Solution and Explanation
Step 1: Understanding the concept of splitting in \( ^1H \) NMR.
In \( ^1H \) NMR, the splitting pattern is determined by the number of adjacent protons (coupling). A triplet occurs when a proton is coupled to two equivalent protons. This will split the signal into three peaks (a triplet), with the coupling constant (\( J \)) determining the spacing between the peaks.
Step 2: Analyzing the compounds.
- **(A)** The compound shows a methylene group (\( CH_2 \)) next to a \( CH_3 \) group, which will split the signal into a triplet.
- **(B)** This compound shows two equivalent methyl groups (\( CH_3 \)) attached to a carbonyl group, which will not show a triplet.
- **(C)** This compound has a benzene ring and a methyl group, but no adjacent equivalent protons that would cause a triplet.
- **(D)** This compound has a hydroxyl group and a bromine atom attached to the benzene ring, but no protons that would create a triplet pattern.
Step 3: Conclusion.
The correct answer is (A), as it is the only compound that will show a triplet in its \( ^1H \) NMR spectrum.
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