To determine the number of peaks into which the methyl group of ethanol splits in its 1H NMR spectrum at 400 MHz, we apply the "n+1" rule. This rule states that a proton (or a group of equivalent protons) will split into n+1 peaks, where n is the number of neighboring protons.
In ethanol (CH3CH2OH), the methyl group (CH3) has two neighboring protons from the methylene group (CH2). Therefore, we can calculate the splitting of the methyl group using the formula:
Splitting = n + 1, where n = 2.
Thus, Splitting = 2 + 1 = 3.
Therefore, the methyl group in the 1H NMR spectrum of ethanol splits into 3 peaks.
| Group I | Group II |
| P) NaCl | 1) Coordination bond |
| Q) $H_2$ | 2) Polar covalent bond |
| R) $Pd-P$ bond in $Pd(PPh_3)_4 | 3) Covalent bond |
| S) $C-Cl$ bond in $CH_3Cl $ | 4) Ionic bond |

