From the balance condition:
\(\frac{R_1}{R_2} = \frac{R_3}{R_4}\)
\(R_1 = R_2 \times \frac{R_3}{R_4}\)
\(R_1 = 300 \times \frac{700}{1500} = 140 \, \Omega\)
Using the inductance formula:
\(L_1 = R_2 R_3 C_4\)
\(L_1 = 300 \times 700 \times 0.8 \times 10^{-6}\)
\(L_1 = 168 \times 10^{-3} \, \text{H} = 0.168 \, \text{H}\)
Using the Q factor formula:
\(Q = \omega C_4 R_4\)
\(Q = 2\pi \times 1100 \times 0.8 \times 10^{-6} \times 1500\)
\(Q = 2\pi \times 1100 \times 1.2 \times 10^{-3}\)
\(Q = 8.29\)
\(R_1 = 140 \, \Omega\), \(L_1 = 0.168 \, \text{H}\), \(Q = 8.29\)
What is the voltage across the inductor at $t=0$? (Circuit diagram provided: A 60V voltage source in series with a switch that closes at $t=0$, a 30 ohm resistor, and a 15H inductor.) 