Step 1: Understanding the Concept:
This problem combines the "together" constraint with permutations of identical items. We must divide by the factorials of repeating letters to avoid overcounting.
Step 2: Key Formula or Approach:
Total = $\frac{(\text{Units})!}{\text{Repeating Consonants}!} \times \frac{(\text{Vowels})!}{\text{Repeating Vowels}!}$
Step 3: Detailed Explanation:
1. Word: ESPECIALLY (10 letters).
2. Vowels: E, E, I, A (4 letters). Consonants: S, P, C, L, L, Y (6 letters).
3. Treat vowels (EEIA) as 1 unit. Total units = 6 consonants + 1 unit = 7 units.
4. Arrange 7 units: Note that 'L' repeats twice.
\[ \text{Ways} = \frac{7!}{2!} = \frac{5040}{2} = 2520 \]
5. Arrange vowels internally: (E, E, I, A). Note that 'E' repeats twice.
\[ \text{Ways} = \frac{4!}{2!} = \frac{24}{2} = 12 \]
6. Total = $2520 \times 12 = 30240$.
Step 4: Final Answer:
The word can be arranged in 30240 ways.