Question:
In graphite the C - C bond length with in the layer is X pm and the distance between two adjacent layers is Y pm. X and Y respectively are
In graphite the C - C bond length with in the layer is X pm and the distance between two adjacent layers is Y pm. X and Y respectively are
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Graphite facts:
\[
\text{C-C bond length} = 141.5\,pm
\]
\[
\text{Interlayer distance} = 340\,pm
\]
Weak interlayer forces are responsible for the lubricating property of graphite.
Updated On: Jun 22, 2026
- 340, 141.5
- 141.5, 340
- 141.5, 154
- 143.5, 340 \bigskip
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The Correct Option is B
Solution and Explanation
Concept:
Graphite consists of planar hexagonal layers of carbon atoms. Each carbon atom is \(sp^2\)-hybridised and bonded to three neighbouring carbon atoms.
Step 1: Determine the C-C bond length within a layer.
Due to resonance and partial double-bond character, the C-C bond length is \[ 141.5 \; pm \] which lies between a single and double bond length.
Step 2: Determine the separation between adjacent layers.
The layers are held together by weak van der Waals forces. The interlayer distance is \[ 340 \; pm \]
Step 3: Match the values with the options.
\[ X=141.5\;pm \] \[ Y=340\;pm \] Therefore, \[ \boxed{(141.5,\;340)} \] \[ \boxed{\text{Option (B)}} \]
Step 1: Determine the C-C bond length within a layer.
Due to resonance and partial double-bond character, the C-C bond length is \[ 141.5 \; pm \] which lies between a single and double bond length.
Step 2: Determine the separation between adjacent layers.
The layers are held together by weak van der Waals forces. The interlayer distance is \[ 340 \; pm \]
Step 3: Match the values with the options.
\[ X=141.5\;pm \] \[ Y=340\;pm \] Therefore, \[ \boxed{(141.5,\;340)} \] \[ \boxed{\text{Option (B)}} \]
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