In Carius method of estimation of halogen, 0.45 g of an organic compound gave 0.36 g of AgBr. Find out the percentage of bromine in the compound.
(Molar masses: AgBr = 188 g mol–1; Br = 80 g mol–1)
(Molar masses: AgBr = 188 g mol–1; Br = 80 g mol–1)
- 34.04%
- 40.04%
- 36.03%
- 38.04%
The Correct Option is A
Solution and Explanation
The correct answer is (A):
188g of AgBr = 80g of Br
0.36g of AgBr = \(\frac{80}{188}\)×0.36
Percentage of Br in given organic compound
= 80×\(\frac{0.36}{188}\)×0.45×100
= 34.04%
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