In Carius method of estimation of halogen, 0.172 g of an organic compound showed presence of 0.08 g of bromine. Which of these is the correct structure of the compound?
Show Hint
- H3C - CH2 - Br
- H3C - Br
The Correct Option is C
Solution and Explanation
(1) \(\mathrm{C_2H_5Br}\), M = 109: % Br = \(\frac{80}{109}\times 100 = 73.4\%\).
(2) \(\mathrm{CH_3Br}\), M = 95: % Br = \(\frac{80}{95}\times 100 = 84.2\%\).
(3) 4-bromoaniline \(\mathrm{C_6H_6BrN}\), M = 172: % Br = \(\frac{80}{172}\times 100 = 46.5\%\).
(4) 2,4-dibromoaniline \(\mathrm{C_6H_5Br_2N}\), M = 251: % Br = \(\frac{160}{251}\times 100 = 63.7\%\).
Only option (3) matches.
Answer: (3) 4-bromoaniline
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