Step 1: Use Energy
-Mass Relation Using Einstein’s mass-energy equivalence: \[ E = mc^2 \] where: - \( m = 1 \times 10^{-3} \) g = \( 1 \times 10^{-6} \) kg, - \( c = 3 \times 10^8 \) m/s.
Step 2: Compute Power Energy released per second: \[ P = (1 \times 10^{-6}) \times (9 \times 10^{16}) \] \[ P = 9 \times 10^{10} \text{ W} = 9 \times 10^7 \text{ kW} \]
In the given circuit, the electric currents through $15\, \Omega$ and $6 \, \Omega$ respectively are

What is the strong nuclear force in nature?
The binding energy of the nucleus is?