Six Sigma quality requires defects per million opportunities (DPMO) to be: \[ \text{DPMO} < 3.4 \] Batch size for each product: \[ 2 \times 10^{7} \] Compute DPMO for each: P: \[ \text{DPMO}_P = \frac{60}{2\times 10^7} \times 10^6 = 3 \] Q: \[ \text{DPMO}_Q = \frac{71}{2\times 10^7} \times 10^6 = 3.55 \] R: \[ 80 \Rightarrow \text{DPMO}_R = 4 \] S: \[ 55 \Rightarrow \text{DPMO}_S = 2.75 \] Interpretation:
- Products P and S have DPMO < 3.4 → satisfy Six Sigma.
- Q and R exceed the limit.
Hence, the correct statement is that only P and S meet Six Sigma quality.
Final Answer: Products P and S conform to six sigma standard.
