Given the relation \( V = 30 + 30l \) and the open circuit voltage \( V = 80 \) volts, we can substitute into the equation:
\[
80 = 30 + 30l.
\]
Solving for \( l \), we get:
\[
30l = 80 - 30 = 50,
\]
\[
l = \frac{50}{30} = 1.6667.
\]
Thus, the maximum possible arc length is \( 1.67 \, {cm} \), rounded to two decimal places.