Question:
In a class of 60 students, 40 opted for NCC, 30 opted for NSS and 20 opted for both NCC and NSS. If one of these students is selected at random, then the probability that the students selected has opted neither for NCC nor for NSS is :
In a class of 60 students, 40 opted for NCC, 30 opted for NSS and 20 opted for both NCC and NSS. If one of these students is selected at random, then the probability that the students selected has opted neither for NCC nor for NSS is :
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Find \(n(\text{NCC}\cup\text{NSS})\) by inclusion-exclusion, then subtract from 60.
Updated On: Nov 5, 2026
- \(\frac{1}{3}\)
- \(\frac{1}{6}\)
- \(\frac{2}{3}\)
- \(\frac{5}{6}\)
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The Correct Option is B
Solution and Explanation
\(n(\text{NCC}\cup\text{NSS})=40+30-20=50\).
Students in neither: \(60-50=10\).
Probability \(=\frac{10}{60}=\frac16\).
Answer: (2) \(\frac{1}{6}\)
Students in neither: \(60-50=10\).
Probability \(=\frac{10}{60}=\frac16\).
Answer: (2) \(\frac{1}{6}\)
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