Question:
In a Carnot engine, the absolute temperature of the source is 25% more than the absolute temperature of the sink. The efficiency of the engine is
In a Carnot engine, the absolute temperature of the source is 25% more than the absolute temperature of the sink. The efficiency of the engine is
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For Carnot engines, always express the temperature ratio correctly when given percentage increases.
Updated On: Mar 18, 2026
10%
50%
25%
20%
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The Correct Option is D
Solution and Explanation
The efficiency of a Carnot engine is given by:
\[
\eta = 1 - \frac{T_C}{T_H}
\]
Given that \( T_H = 1.25 T_C \), we substitute:
\[
\eta = 1 - \frac{T_C}{1.25T_C}
\]
\[
= 1 - \frac{1}{1.25} = 1 - 0.8 = 0.2
\]
\[
= 20\%
\]
Thus, the efficiency of the engine is 20\%.
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