Step 1: Recall the volumetric quantities needed.
Marshall mix design defines: \(G_t\) = theoretical maximum specific gravity (mix with zero air voids), \(V_a\) = air voids (%), \(V_b\) = volume of bitumen (%), \(VMA\) = voids in mineral aggregate \(= V_a+V_b\), and \(VFB = \dfrac{V_b}{VMA}\times100\), the fraction of the VMA actually filled by the binder.
Step 2: Find the theoretical maximum specific gravity, \(G_t\).
For 100 kg of mix, using the given percentages by weight and specific gravities of each ingredient,
\[ G_t = \frac{100}{\dfrac{58}{2.68}+\dfrac{25}{2.45}+\dfrac{12}{2.42}+\dfrac{5}{1.15}} \]
Compute each term: \(58/2.68=21.642\), \(25/2.45=10.204\), \(12/2.42=4.959\), \(5/1.15=4.348\). Sum \(=41.153\).
\[ G_t = \frac{100}{41.153}=2.430 \]
Step 3: Find the air voids, \(V_a\).
Air voids compare the actual (bulk) specific gravity \(G_m=2.2\) with the zero-void value \(G_t\):
\[ V_a = \frac{G_t-G_m}{G_t}\times100 = \frac{2.430-2.2}{2.430}\times100=9.47\% \]
Step 4: Find the volume of bitumen, \(V_b\).
\[ V_b = \frac{G_m\times W_b}{G_b} = \frac{2.2\times5}{1.15}=\frac{11}{1.15}=9.57\% \]
where \(W_b=5\) is the percent bitumen by weight of the total mix and \(G_b=1.15\) its specific gravity.
Step 5: Find VMA, then VFB.
\[ VMA = V_a+V_b=9.47+9.57=19.03\% \]
\[ VFB = \frac{V_b}{VMA}\times100=\frac{9.57}{19.03}\times100=50.3\% \]
Final Answer:
Rounded to the nearest integer, roughly half of the void space between the aggregate particles is filled with bitumen.
\[ \boxed{VFB \approx 50\%} \]