Step 1: Modulus of \( z \).
Since \( z = e^{i\theta} \), the modulus of \( z \) is \( |z| = 1 \).
Step 2: Evaluating the given options.
We need to check which of the given options has a modulus of 1:
- \( \frac{1}{z} \) has modulus 1, because \( \left| \frac{1}{z} \right| = |z|^{-1} = 1 \),
- \( z + \frac{1}{z} \) is a real number, and since \( z = e^{i\theta} \), \( \frac{1}{z} = e^{-i\theta} \). Thus, \( z + \frac{1}{z} = e^{i\theta} + e^{-i\theta} = 2\cos(\theta) \), which has modulus 1 for specific values of \( \theta \).
Step 3: Conclusion.
The correct answer is (3) \( z + \frac{1}{z} \).