Question:

If \(|z - 3 + 2i| \leq 4\) then the difference between the greatest value and the least value of \(|z|\) is :

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The region is a disc centred at 3 - 2i with radius 4; check whether the origin lies inside it.
Updated On: Nov 11, 2026
  • \(2\sqrt{13}\)
  • \(8\)
  • \(4+\sqrt{13}\)
  • \(\sqrt{13}\)
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The Correct Option is C

Solution and Explanation

\(|z-(3-2i)| \leq 4\) is the closed disc with centre \(C(3,-2)\) and radius 4.
Distance of the origin from the centre: \(OC = \sqrt{9+4} = \sqrt{13} \approx 3.61 < 4\), so the origin lies inside the disc.
Greatest \(|z|\) = \(OC + 4 = 4+\sqrt{13}\).
Least \(|z|\) = 0 (the point \(z=0\) belongs to the disc).
Difference \(= 4+\sqrt{13} - 0 = 4+\sqrt{13}\).
Answer: (3) \(4+\sqrt{13}\)
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