Step 1: Split the interval according to the greatest integer function.& nbsp;
Since
\[ [x-2] = \begin{cases} -2, & amp; 0 \le x < 1,\\ -1, & amp; 1 \le x < 2,\\ 0, & amp; 2 \le x < 3,\\ 1, & amp; 3 \le x < 4,\\ 2, & amp; 4 \le x < 5, \end{cases} \]
the integral can be written as
\[ \int_{0}^{5}[x-2]\,dx = \int_{0}^{1}(-2)\,dx + \int_{1}^{2}(-1)\,dx + \int_{2}^{3}0\,dx + \int_{3}^{4}1\,dx + \int_{4}^{5}2\,dx. \]
Step 2: Evaluate each integral.
\[ =(-2)(1)+(-1)(1)+0(1)+(1)(1)+(2)(1). \] \[ =-2-1+0+1+2=0. \]
Hence,
\[ \boxed{\int_{0}^{5}[x-2]\,dx=0.} \]
Therefore, the correct option is \[ \boxed{(A)}. \]