Question

If \((\frac {x}{3}+1, \frac {y-2}{3}) = (\frac {5}{3}, \frac {1}{3})\), Find the value of x and y.

Answer 1

It is given that \((\frac {x}{3}+1, \frac {y-2}{3}) = (\frac {5}{3}, \frac {1}{3})\).

Since the ordered pairs are equal, the corresponding elements will also be equal.

\((\frac {x}{3}+1, \frac {y-2}{3}) = (\frac {5}{3}, \frac {1}{3})\)

Therefore, 

\(\frac {x}{3}+1=\frac {5}{3}\)

⇒ \(\frac{x}{3} = \frac{5}{3} -1,\frac{y-2}{3} = \frac{1}{3}\)

⇒\(\frac{x}{3} = \frac{2}{3}, y = \frac{1}{3}+\frac{2}{3}\)

⇒ x=2, y=1