Question:

If \( w = \log_e z = \log_e(x+iy) \), where \( i = \sqrt{-1} \), then which one of the following statements is correct?

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Split w into its real and imaginary parts using z = re^{i theta} and check where the Cauchy-Riemann equations fail.
Updated On: Jul 27, 2026
  • \( w \) is analytic everywhere except at \( z = 0 \)
  • \( w \) is non-analytic everywhere
  • The conjugate functions of \( w \) are \( \log_e(x^2+y^2) \) and \( \log_e(x^2-y^2) \)
  • The conjugate functions of \( w \) are \( \tan^{-1}(x/y) \) and \( \tan^{-1}(y/x) \)
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The Correct Option is A

Solution and Explanation

This question checks whether you know where the complex logarithm fails to be analytic, and what its real and imaginary parts look like in Cartesian form.

Write \( z = x+iy = re^{i\theta} \), so \( w = \log_e z = \log_e r + i\theta = \dfrac{1}{2}\log_e(x^2+y^2) + i\tan^{-1}(y/x) \). The real part is \( u = \dfrac{1}{2}\log_e(x^2+y^2) \) and the imaginary part is \( v = \tan^{-1}(y/x) \).

  1. \( w \) is analytic everywhere except at \( z=0 \): correct. The derivative \( dw/dz = 1/z \) exists everywhere \( z \neq 0 \). The only trouble point is the origin, where \( \log_e z \) is undefined.
  2. \( w \) is non-analytic everywhere: wrong. \( u \) and \( v \) satisfy the Cauchy Riemann equations at every point away from the origin, so \( w \) is analytic there.
  3. The conjugate functions are \( \log_e(x^2+y^2) \) and \( \log_e(x^2-y^2) \): wrong. The true real part carries a factor of one half, and the imaginary part is an inverse tangent, not another logarithm.
  4. The conjugate functions are \( \tan^{-1}(x/y) \) and \( \tan^{-1}(y/x) \): wrong. Neither expression matches \( u \), and only \( \tan^{-1}(y/x) \) actually shows up, as the imaginary part alone.

So the correct statement is that \( w = \log_e z \) is analytic everywhere in the plane except at the single point \( z = 0 \).

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