Question:
If $v_0$ is threshold frequency and $v$ is incident frequency, velocity of photoelectrons is:
If $v_0$ is threshold frequency and $v$ is incident frequency, velocity of photoelectrons is:
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Photoelectron velocity depends on excess frequency above threshold.
Updated On: Jun 17, 2026
- $v=\sqrt{\frac{2h}{m}(v-v_0)}$
- $v=\sqrt{\frac{2h}{m}(v_0-v)}$
- $v=\sqrt{\frac{m}{2h}(v-v_0)}$
- $v=\sqrt{\frac{m}{2hc}(v_0-v)}$
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The Correct Option is A
Solution and Explanation
Step 1: Einstein photoelectric equation: \[ K_{\max} = h(v - v_0) \]
Step 2: Kinetic energy relation: \[ \frac{1}{2}mv^2 = h(v - v_0) \]
Step 3: Solve for velocity: \[ v = \sqrt{\frac{2h}{m}(v - v_0)} \]
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