For the system of equations to have infinitely many solutions, the determinant of the coefficient matrix (\(\Delta\)) and the determinants of the matrices obtained by replacing each column with the constant terms (\(\Delta_x\), \(\Delta_y\), \(\Delta_z\)) must all be equal to zero. The coefficient matrix is: \[ \begin{pmatrix} 1 & 1 & a \\ 2 & 5 & 2 \\ 1 & 2 & 3 \end{pmatrix} \] \[ \Delta = \begin{vmatrix} 1 & 1 & a \\ 2 & 5 & 2 \\ 1 & 2 & 3 \end{vmatrix} = 1(15 - 4) - 1(6 - 2) + a(4 - 5) = 11 - 4 - a = 7 - a. \] For infinitely many solutions, \(\Delta = 0\), so \(7 - a = 0 \Rightarrow a = 7\). Now, let's calculate \(\Delta_x\): \[ \Delta_x = \begin{vmatrix} b & 1 & 7 \\ 6 & 5 & 2 \\ 3 & 2 & 3 \end{vmatrix} = b(15 - 4) - 1(18 - 6) + 7(12 - 15) = 11b - 12 - 21 = 11b - 33. \] For infinitely many solutions, \(\Delta_x = 0\), so \(11b - 33 = 0 \Rightarrow b = 3\). Now we can calculate \(2a + 3b = 2(7) + 3(3) = 14 + 9 = 23\).
Consider the parabola \(25[(x-2)^2 + (y+5)^2] = (3x+4y-1)^2\), match the characteristic of this parabola given in List-I with its corresponding item in List-II.

Two positively charged particles \(m_1\) and \(m_2\) have been accelerated across the same potential difference of 200 keV. Given mass of \(m_1 = 1 \,\text{amu}\) and \(m_2 = 4 \,\text{amu}\). The de Broglie wavelength of \(m_1\) will be \(x\) times that of \(m_2\). The value of \(x\) is _______ (nearest integer). 