Question:

If the standard molar enthalpy change for combustion of graphite powder is \(-2.48\times 10^{2}\) kJ \(\mathrm{mol^{-1}}\), the amount of heat generated on combustion of 1 g of graphite powder is ___________ kJ. (Nearest integer)

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Convert 1 g of carbon to moles (molar mass 12 g/mol) and multiply by the molar heat of combustion.
Updated On: Nov 4, 2026
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Correct Answer: 21

Solution and Explanation

Moles of graphite in 1 g = \(\dfrac{1}{12}\) mol.
Heat released = \(\dfrac{1}{12}\times 248 = 20.67\) kJ
Nearest integer = 21
Answer: 21
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