Question

If the product of zeroes of a polynomial \(x^{2}-9x+2a\) is \(8\), then the value of \(a\) will be

• A. \(4\)
• B. \(-4\)
• C. \(9\)
• D. \(-9\)

Hint:

In a monic quadratic, the constant term equals the product of the roots.

Answer 1

The Correct Option is A

Step 1: Use product of roots.
For \(x^{2}+px+q\), \(\alpha\beta=q\). Here \(q=2a\).
Step 2: Set equal to 8.
\(2a=8 \Rightarrow a=4.\)