If the principal quantum number n = 6, the correct sequence of filling of electrons will be:
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- \(ns\rightarrow(n-1)d\rightarrow(n-2)f\rightarrow np\)
- \(ns\rightarrow np\rightarrow(n-1)d\rightarrow(n-2)f\)
- \(ns\rightarrow(n-2)f\rightarrow np\rightarrow(n-1)d\)
- \(ns\rightarrow(n-2)f\rightarrow(n-1)d\rightarrow np\)
The Correct Option is D
Solution and Explanation
Order: 6s, then 4f (n=4), then 5d (n=5), then 6p (n=6).
That is \(ns\rightarrow(n-2)f\rightarrow(n-1)d\rightarrow np\).
Answer: (4) \(ns\rightarrow(n-2)f\rightarrow(n-1)d\rightarrow np\)
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