Step 1: Understanding the Question:
This question is from Mensuration, dealing with the comparison of areas and boundaries of different shapes (circle and square).
We are given that their boundaries are equal, and we need to find the ratio of their areas.
Step 2: Key Formula or Approach:
Let the radius of the circle be \(r\), and the side length of the square be \(a\).
1. Perimeter of the circle (circumference) is:
\[ C = 2\pi r \]
2. Perimeter of the square is:
\[ P = 4a \]
Given that \(C = P\), we can express \(a\) in terms of \(r\).
Then, we compute the ratio of their areas:
\[ \text{Ratio} = \frac{\text{Area of Circle}}{\text{Area of Square}} = \frac{\pi r^2}{a^2} \]
Step 3: Detailed Explanation:
Set the perimeters equal:
\[ 2\pi r = 4a \]
Simplify to express \(a\) in terms of \(r\):
\[ a = \frac{2\pi r}{4} = \frac{\pi r}{2} \]
Now, write the formula for the areas:
- Area of the circle:
\[ A_{\text{circle}} = \pi r^2 \]
- Area of the square:
\[ A_{\text{square}} = a^2 \]
Substitute \(a = \frac{\pi r}{2}\) into the square's area formula:
\[ A_{\text{square}} = \left(\frac{\pi r}{2}\right)^2 = \frac{\pi^2 r^2}{4} \]
Calculate the ratio of the areas:
\[ \frac{A_{\text{circle}}}{A_{\text{square}}} = \frac{\pi r^2}{\frac{\pi^2 r^2}{4}} \]
Cancel \(r^2\) and simplify the fraction:
\[ \frac{A_{\text{circle}}}{A_{\text{square}}} = \frac{\pi}{\frac{\pi^2}{4}} = \frac{4}{\pi} \]
Substitute \(\pi = \frac{22}{7}\):
\[ \frac{A_{\text{circle}}}{A_{\text{square}}} = \frac{4}{\frac{22}{7}} = \frac{4 \times 7}{22} \]
\[ \frac{A_{\text{circle}}}{A_{\text{square}}} = \frac{28}{22} = \frac{14}{11} \]
Step 4: Final Answer:
The ratio of their areas is 14 : 11.