If the local maximum value of the function f( x )=\((\frac{√3e}{2 sin x} )^{ sin^2x}\) ,\( x ∈ ( 0,\frac{π}{2} )\), is \(\frac{k}{e}\), then \((\frac{k}{e})^8+\frac{k^8}{e^5}+k^8 \) is equal to
- e5+e6+e11
- e3+e6+e10
- e3+e5+e11
- e3+e6+e11
The Correct Option is D
Solution and Explanation
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