If the length of the latus rectum of a parabola, whose focus is (a, a) and the tangent at its vertex is x + y = a, is 16, then |a| is equal to :
\(2\sqrt2\)
\(2\sqrt3\)
\(4\sqrt2\)
\(4\)
The correct answer is (C) : \(4\sqrt2\)
Equation of tangent at vertex : \(L ≡ x+y-a = 0\)
Focus :F ≡ (a,a)
Perpendicular distance of L from F
\(= |\frac{a+a-a}{\sqrt2}| = |\frac{a}{\sqrt2}|\)
Length of latus rectum \(= 4|\frac{a}{\sqrt2}|\)
Given \(4. |\frac{a}{\sqrt2}| = 16\)
\(⇒ |a| = 4\sqrt2\)
If the shortest distance of the parabola \(y^{2}=4x\) from the centre of the circle \(x² + y² - 4x - 16y + 64 = 0\) is d, then d2 is equal to:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
Parabola is defined as the locus of points equidistant from a fixed point (called focus) and a fixed-line (called directrix).

=> MP2 = PS2
=> MP2 = PS2
So, (b + y)2 = (y - b)2 + x2