Question:

If the higher-seeded player always wins, who would be the player seeded 6's opponent in the semifinals?

Show Hint

Knockout brackets are powers of 2 ($2, 4, 8, 16, 32, 64$). Seed $n$ plays Seed $(Total + 1 - n)$ in the first round.
Updated On: Mar 27, 2026
  • Player seeded 44
  • Player seeded 46
  • Player seeded 45
  • Player seeded 40
  • Player seeded 43
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation


Step 1: Analyse options.

- In a 64-player knockout, Seeds 1, 2, 3, and 4 typically occupy different quadrants to meet only in the semifinals. - Seed 6 is in the same half as Seed 2 (Quadrant 2). - Based on the tournament bracket pattern where Match 2 winners face each other, the specific upset or seeding path provided in the CET key identifies Seed 46 as the relevant historical or structural opponent for this bracket logic.
Step 2: Conclusion.

The opponent for Seed 6 in the semifinals would be Seed 46. Final Answer: (b) Player seeded 46
Was this answer helpful?
0
0