Question:
If the data rate of delta modulator output is 43.2 kbps, for the input signal of 3.6 kHz, then the sampling rate used is equal to,
If the data rate of delta modulator output is 43.2 kbps, for the input signal of 3.6 kHz, then the sampling rate used is equal to,
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Remember the data rate in delta modulation is same as the sampling frequency. Nyquist frequency is twice the signal frequency.
Updated On: Feb 27, 2025
- 4 times the Nyquist rate
- 6 times the Nyquist rate
- 12 times the Nyquist rate
- 3 times the Nyquist rate
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The Correct Option is B
Solution and Explanation
Step 1: First we calculate the Nyquist frequency: \[ f_{nyquist} = 2 \times 3.6 kHz = 7.2 kHz \]
Step 2: The sampling frequency \(f_s\) is same as the data rate in a delta modulator, that is 43.2 kbps.
Step 3: To find what multiple of Nyquist rate the sampling frequency is, we calculate: \[ \frac{43.2 kHz}{7.2 kHz} = 6 \] Therefore, the sampling frequency is 6 times the Nyquist rate.
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