Let the radius of the circle be \( r \) and the side of the square be \( s \).
\[
\pi r^2 = s^2
\]
\[
s = \sqrt{\pi r^2} = r\sqrt{\pi}
\]
Perimeter of Circle:
\[
P_C = 2\pi r
\]
Perimeter of Square:
\[
P_S = 4s = 4r\sqrt{\pi}
\]
Taking the ratio:
\[
\frac{P_C}{P_S} = \frac{2\pi r}{4r\sqrt{\pi}} = \frac{\pi}{2}
\]