Step 1: Given \( \tan \theta = \frac{3}{4} \), we can use the identity \( \tan \theta = \frac{\sin \theta}{\cos \theta} \).
Step 2: Let \( \sin \theta = 3k \) and \( \cos \theta = 4k \) for some constant \( k \).
Step 3: Using the Pythagorean identity \( \sin^2 \theta + \cos^2 \theta = 1 \):
\[
(3k)^2 + (4k)^2 = 1
\]
\[
9k^2 + 16k^2 = 1
\]
\[
25k^2 = 1
\]
\[
k^2 = \frac{1}{25}
\]
\[
k = \frac{1}{5}
\]
Step 4: Therefore, \( \sin \theta = 3k = \frac{3}{5} \).
Thus, the correct answer is \( \boxed{\frac{3}{5}} \).