Step 1: Take the parametric coordinates of the parabola.
For the parabola
\[
y^2=4ax,
\]
a general point is
\[
P(at^2,\;2at).
\]
Hence,
\[
y=2at.
\]
Step 2: Find the subtangent and subnormal.
The slope of the tangent is
\[
\frac{dy}{dx}
=
\frac1t.
\]
Therefore,
Length of subtangent:
\[
y\cdot\frac{dx}{dy}
=
y\left(\frac1{dy/dx}\right)
=
2at\cdot t
=
2at^2.
\]
Length of subnormal:
\[
y\cdot\frac{dy}{dx}
=
2at\cdot\frac1t
=
2a.
\]
Thus, the three quantities are
\[
2at^2,\qquad
2at,\qquad
2a.
\]
Step 3: Check the progression.
Now,
\[
(2at)^2
=
(2at^2)(2a).
\]
Hence,
\[
(\text{\(y\)-coordinate})^2
=
(\text{subtangent})
\times
(\text{subnormal}).
\]
Therefore, the three quantities are in
\[
\boxed{\text{geometric progression}.}
\]
Thus,
\[
\boxed{(D)}
\]
is the correct answer.