Question:

If \( P = \{5m : m \in N\} \) and \( Q = \{5^m : m \in N\} \), where \( N \) is set of natural numbers, then

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Multiples of a number form a larger set than its powersAlways check with a simple counterexample to verify subset relations.
Updated On: May 6, 2026
  • \( P = Q \)
  • \( P \subset Q \)
  • \( Q \subset P \)
  • \( P \cup Q = N \)
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The Correct Option is C

Solution and Explanation

Step 1: Write elements of set \( P \).
\[ P = \{5m : m \in N\} \]
So elements are:
\[ 5, 10, 15, 20, 25, \ldots \]

Step 2: Write elements of set \( Q \).

\[ Q = \{5^m : m \in N\} \]
So elements are:
\[ 5, 25, 125, 625, \ldots \]

Step 3: Compare both sets.

Every element of \( Q \) is a multiple of 5.
So all elements of \( Q \) belong to \( P \).

Step 4: Check reverse inclusion.

Not all multiples of 5 are powers of 5.
For example:
\[ 10 \in P \text{ but } 10 \notin Q \]

Step 5: Conclusion about sets.

\[ Q \subset P \]

Step 6: Match with options.

Correct option is (C).

Step 7: Final conclusion.

\[ \boxed{Q \subset P} \]
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