If \(n = \frac{16}{81}\), what is the value of \(\sqrt{n}\)?
*(Note: The OCR included a typo, which has been corrected to the most logical question based on the options.)*
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Memorizing perfect squares (like \(4^2=16\), \(9^2=81\), etc.) is essential for saving time on arithmetic and algebra problems on standardized tests.
Step 1: Understanding the Concept:
The problem asks to find the square root of a given fraction. The square root of a fraction is the square root of the numerator divided by the square root of the denominator. Step 2: Key Formula or Approach:
The property of square roots we use is:
\[ \sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}} \]
Step 3: Detailed Explanation:
We are given \(n = \frac{16}{81}\) and we need to find \(\sqrt{n}\).
Substitute the value of n:
\[ \sqrt{n} = \sqrt{\frac{16}{81}} \]
Apply the square root property:
\[ \sqrt{\frac{16}{81}} = \frac{\sqrt{16}}{\sqrt{81}} \]
Calculate the square roots of the numerator and the denominator:
\[ \sqrt{16} = 4 \]
\[ \sqrt{81} = 9 \]
Combine the results:
\[ \sqrt{n} = \frac{4}{9} \]
Step 4: Final Answer:
The value of \(\sqrt{n}\) is \(\frac{4}{9}\).