Question

If \( n \) electric dipoles are situated inside a closed surface, the total electric flux coming out from the closed surface will be:

• A. \( \frac{q}{\varepsilon_0} \)
• B. \( \frac{2q}{\varepsilon_0} \)
• C. \( \frac{nq}{\varepsilon_0} \)
• D. zero

Hint:

Remember: Gauss's Law depends on net enclosed charge. Dipoles do not contribute to net charge since \( +q + (-q) = 0 \).

Answer 1

The Correct Option is D

According to Gauss’s Law, the total electric flux through a closed surface depends only on the net charge enclosed: \[ \Phi_E = \frac{q_{\text{net}}}{\varepsilon_0}. \] An electric dipole consists of two equal and opposite charges. The net charge of a dipole is zero. So, even if there are \( n \) dipoles inside the surface, the total net charge enclosed remains zero: \[ q_{\text{net}} = 0 \quad \Rightarrow \quad \Phi_E = 0. \]