If 
then the value of \( m \) is:
Step 1: Continuity Condition.
For the function to be continuous at \( x = 0 \), we must have: \[ \lim_{x \to 0} f(x) = f(0) \] Thus, we need to calculate \( \lim_{x \to 0} \frac{\sin 8x}{5x} \).
Step 2: Finding the limit.
Using the standard limit \( \lim_{x \to 0} \frac{\sin kx}{x} = k \), we get: \[ \lim_{x \to 0} \frac{\sin 8x}{5x} = \frac{8}{5} \] Step 3: Conclusion.
For the function to be continuous, we must have: \[ f(0) = m + 1 = \frac{8}{5} \] Thus, solving for \( m \), we get: \[ m + 1 = \frac{8}{5} \quad \Rightarrow \quad m = \frac{8}{5} - 1 = \frac{5}{8} \] Step 4: Final Answer.
Therefore, the value of \( m \) is \( \frac{5}{8} \), corresponding to option (A).
If 
then \( y \) is equal to: