Step 1: Use the identity between sine and cosine.}
We know that
\[
\sin^2 A + \cos^2 A = 1
\]
Given that
\[
\cos A = \frac{3}{5}
\]
So,
\[
\cos^2 A = \left(\frac{3}{5}\right)^2 = \frac{9}{25}
\]
Step 2: Find the value of \( \sin^2 A \).}
Substituting in the identity, we get
\[
\sin^2 A = 1 - \frac{9}{25} = \frac{25}{25} - \frac{9}{25} = \frac{16}{25}
\]
Step 3: Find the value of \( \sin A \).}
Taking the positive square root for an acute angle,
\[
\sin A = \sqrt{\frac{16}{25}} = \frac{4}{5}
\]
Step 4: Find the value of \( \tan A \).}
Now,
\[
\tan A = \frac{\sin A}{\cos A} = \frac{\frac{4}{5}}{\frac{3}{5}} = \frac{4}{3}
\]
Step 5: Write the final answer.}
Therefore,
\[
\sin A = \frac{4}{5}, \qquad \tan A = \frac{4}{3}
\]