From the given quadratic equation \( x^2 - 8x + 5 = 0 \), the sum and product of the roots \( \alpha \) and \( \beta \) are:
\[
\alpha + \beta = -\frac{-8}{1} = 8, \quad \alpha \beta = \frac{5}{1} = 5.
\]
We need to find \( \alpha^2 + \beta^2 \). Using the identity:
\[
\alpha^2 + \beta^2 = (\alpha + \beta)^2 - 2\alpha \beta,
\]
we substitute the values of \( \alpha + \beta \) and \( \alpha \beta \):
\[
\alpha^2 + \beta^2 = 8^2 - 2 \times 5 = 64 - 10 = 54.
\]
Thus, the value of \( \alpha^2 + \beta^2 \) is \( \boxed{54} \).